5^+(6-x)=2

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Solution for 5^+(6-x)=2 equation: 



5^+(6-x)=2

We move all terms to the left:

5^+(6-x)-(2)=0

determiningTheFunctionDomain
(6-x)-2+5^=0

We add all the numbers together, and all the variables

(-1x+6)-2+5^=0

We add all the numbers together, and all the variables

(-1x+6)=0

We get rid of parentheses

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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